What is the domain of f(x)=-1-sqrt(289-x^2) ?

The domain of f(x)=-1-sqrt(289-x^2) is -17<= x<= 17

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domain of f(x)=-1-sqrt(289-x^2)

domain

f (x) = - 1 - 289 - x^{2}

- 17 \leq x \leq 17

Interval Notation

[- 17, 17]

Solution steps

Find non-negative values for radicals:

- 17 \leq x \leq 17

The function domain

- 17 \leq x \leq 17

y = 25 - 5^{x}

y = 1 - 2^{x}

g (x) = \frac{2 x + 3}{3 x - 2}

f (x) = 2 - x

\frac{1}{x ^{2} - 36}

What is the domain of f(x)=-1-sqrt(289-x^2) ?
The domain of f(x)=-1-sqrt(289-x^2) is -17<= x<= 17