What is the domain of cos(sqrt(1-x^2)) ?

The domain of cos(sqrt(1-x^2)) is -1<= x<= 1

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domain of cos(sqrt(1-x^2))

domain

cos (1 - x^{2})

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

The function domain

- 1 \leq x \leq 1

\frac{2 x + 7}{x - ∣ x ∣}

(x + 9)^{2} - 3

x^{2} - 81

f (x) = 2 x - x^{2} + 8

y = 8 - 4 x

What is the domain of cos(sqrt(1-x^2)) ?
The domain of cos(sqrt(1-x^2)) is -1<= x<= 1