What is the domain of f(x)=(sqrt(x+15))/(2x+7) ?

The domain of f(x)=(sqrt(x+15))/(2x+7) is -15 -7/2

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domain of f(x)=(sqrt(x+15))/(2x+7)

domain

f (x) = \frac{x + 15}{2 x + 7}

- 15 \leq x < - \frac{7}{2} or x > - \frac{7}{2}

Interval Notation

[- 15, - \frac{7}{2}) \cup (- \frac{7}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 15

Find undefined (singularity) points:

x = - \frac{7}{2}

Combine real regions and undefined points for final function domain

- 15 \leq x < - \frac{7}{2} or x > - \frac{7}{2}

y = x^{2} - 3 x

f (x) = ∣ - ln (x) ∣

3^{x - 3}

4^{x - 3}

lo g_{8} (x - 1) + 1

What is the domain of f(x)=(sqrt(x+15))/(2x+7) ?
The domain of f(x)=(sqrt(x+15))/(2x+7) is -15<= x<-7/2 \lor x>-7/2