What is the critical f(x)= 1/(z-7)-1/z ?

The critical f(x)= 1/(z-7)-1/z is z= 7/2

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critical f(x)= 1/(z-7)-1/z

critical points

f (x) = \frac{1}{z - 7} - \frac{1}{z}

z = \frac{7}{2}

Solution steps

\frac{1}{z - 7} - \frac{1}{z}

Find where

f^{'} (z)

is equal to zero or undefined

z = \frac{7}{2}, z = 0, z = 7

Identify critical points not in

f (z)

domain

Domain of

\frac{1}{z - 7} - \frac{1}{z} : z < 0 or 0 < z < 7 or z > 7

\frac{1}{z - 7} - \frac{1}{z}

is not defined at

z = 0, z = 7

, therefore:

z = \frac{7}{2}

1 + x^{2}

(- 4, 3), (3, - 4)

y = sec (x)

f (x) = \frac{1}{x - 1} + \frac{1}{x - 2}

f (x) = x - 12

What is the critical f(x)= 1/(z-7)-1/z ?
The critical f(x)= 1/(z-7)-1/z is z= 7/2