What is the domain of 1/(sqrt(25-x^2)) ?

The domain of 1/(sqrt(25-x^2)) is -5<x<5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of 1/(sqrt(25-x^2))

domain

\frac{1}{25 - x ^{2}}

- 5 < x < 5

Interval Notation

(- 5, 5)

Solution steps

Find non-negative values for radicals:

- 5 \leq x \leq 5

Find undefined (singularity) points:

x = 5, x = - 5

Combine real regions and undefined points for final function domain

- 5 < x < 5

tanh (z)

\frac{x + 7}{x}

x^{2} - \frac{4}{x}

f (x) = \frac{x ^{3}}{- x ^{2} + 4}

What is the domain of 1/(sqrt(25-x^2)) ?
The domain of 1/(sqrt(25-x^2)) is -5<x<5