What is the domain of f(x)=(10)/(x^2+1) ?

The domain of f(x)=(10)/(x^2+1) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(10)/(x^2+1)

domain

f (x) = \frac{10}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x}{x ^{2} + x - 2}

x^{\frac{1}{5}} (x - 4)

f (x) = \frac{x}{x ^{2} + x + 4}

\frac{∣ x ^{2} - 4 ∣ + 3 x}{x ^{2} - ∣ x + 1 ∣}

y = \frac{x - 1}{x - 3}

What is the domain of f(x)=(10)/(x^2+1) ?
The domain of f(x)=(10)/(x^2+1) is -infinity <x<infinity