What is the domain of sqrt(1-\sqrt{4-x^2)} ?

The domain of sqrt(1-\sqrt{4-x^2)} is -2<= x<=-sqrt(3)\lor sqrt(3)<= x<= 2

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domain of sqrt(1-\sqrt{4-x^2)}

domain

1 - 4 - x^{2}

- 2 \leq x \leq - 3 or 3 \leq x \leq 2

Interval Notation

[- 2, - 3] \cup [3, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq - 3 or 3 \leq x \leq 2

The function domain

- 2 \leq x \leq - 3 or 3 \leq x \leq 2

f (x) = \frac{5 x - 6}{5 x + 35}

f (x) = \frac{x + 4}{x ^{2} - 3 x - 28}

y = \frac{2 x - 1}{6 x ^{2} - 5 x - 6}

f (x) = \frac{2 x}{2 x ^{3} + x ^{2} - 10 x}

f (x) = \frac{3 x + 6}{x ^{2} - x - 2}

What is the domain of sqrt(1-\sqrt{4-x^2)} ?
The domain of sqrt(1-\sqrt{4-x^2)} is -2<= x<=-sqrt(3)\lor sqrt(3)<= x<= 2