What is the domain of y=(sqrt(4x+3))/(sqrt(2x-1)) ?

The domain of y=(sqrt(4x+3))/(sqrt(2x-1)) is x> 1/2

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domain of y=(sqrt(4x+3))/(sqrt(2x-1))

domain

y = \frac{4 x + 3}{2 x - 1}

x > \frac{1}{2}

Interval Notation

(\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

Find undefined (singularity) points:

x = \frac{1}{2}

Combine real regions and undefined points for final function domain

x > \frac{1}{2}

cos (\frac{1}{x})

f (x) = \frac{x + 1}{2 - x}

f (x) = e^{c o s (x)} lo g_{10} (x)

\frac{2 x}{( x - 2 ) ( x - 7 )}

f (x) = - 4 x + 8

What is the domain of y=(sqrt(4x+3))/(sqrt(2x-1)) ?
The domain of y=(sqrt(4x+3))/(sqrt(2x-1)) is x> 1/2