What is the domain of f(x)=sqrt(((4x+3))/(2x-1)) ?

The domain of f(x)=sqrt(((4x+3))/(2x-1)) is x 1/2

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domain of f(x)=sqrt(((4x+3))/(2x-1))

domain

f (x) = \frac{( 4 x + 3 )}{2 x - 1}

x \leq - \frac{3}{4} or x > \frac{1}{2}

Interval Notation

Solution steps

Find non-negative values for radicals:

x \leq - \frac{3}{4} or x > \frac{1}{2}

Find undefined (singularity) points:

x = \frac{1}{2}

Combine real regions and undefined points for final function domain

x \leq - \frac{3}{4} or x > \frac{1}{2}

y = \frac{2 x ^{2} - 5 x + 3}{4 x - 8}

f (x) = arctan (x^{2} + x - 2)

- (x - 1)^{3} (x + 3)^{2}

f (x) = - x^{2} - 4 x + 2

f (x) = - x^{2} - 4 x + 5

What is the domain of f(x)=sqrt(((4x+3))/(2x-1)) ?
The domain of f(x)=sqrt(((4x+3))/(2x-1)) is x<=-3/4 \lor x> 1/2