What is the domain of log_{1/3}((x^2-x-6)/2)+x+1 ?

The domain of log_{1/3}((x^2-x-6)/2)+x+1 is x 3

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domain of log_{1/3}((x^2-x-6)/2)+x+1

domain

lo g_{\frac{1}{3}} (\frac{x ^{2} - x - 6}{2}) + x + 1

x < - 2 or x > 3

Interval Notation

(- \infty, - 2) \cup (3, \infty)

Solution steps

Find positive values for logs:

x < - 2 or x > 3

The function domain

x < - 2 or x > 3

f (x) = x + 9

f (x) = \frac{2 x ^{2}}{x ^{2} - 6 x - 7}

f (x) = (ln (x))

3 x^{3} - 6 x^{2} + 15 x + 21

\frac{x ^{3} - 27}{5 x ^{2} + 6}

What is the domain of log_{1/3}((x^2-x-6)/2)+x+1 ?
The domain of log_{1/3}((x^2-x-6)/2)+x+1 is x<-2\lor x>3