What is the domain of (sqrt(x+14))^2-14 ?

The domain of (sqrt(x+14))^2-14 is x>=-14

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domain of (sqrt(x+14))^2-14

domain

(x + 14)^{2} - 14

x \geq - 14

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq - 14

The function domain

x \geq - 14

\frac{x + 1}{x - 2}

f (x) = - x^{2} - x - 1

3 + x

\frac{5 x ^{3} - 8}{1 + x + x ^{2}}

12 - 2 x

What is the domain of (sqrt(x+14))^2-14 ?
The domain of (sqrt(x+14))^2-14 is x>=-14