What is the domain of h(x)=\sqrt[3]{3x+1} ?

The domain of h(x)=\sqrt[3]{3x+1} is -infinity <x<infinity

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domain of h(x)=\sqrt[3]{3x+1}

domain

h (x) = 3 3 x + 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 3 x^{- 2}

g (x) = 3^{x} + 3

∣ x + 2 ∣

y = arctanh (x)

f (x) = lo g_{2} (\frac{6}{x + 2} + 4)

What is the domain of h(x)=\sqrt[3]{3x+1} ?
The domain of h(x)=\sqrt[3]{3x+1} is -infinity <x<infinity