What is the domain of g(x)=sqrt(x^2-3x) ?

The domain of g(x)=sqrt(x^2-3x) is x = 3

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domain of g(x)=sqrt(x^2-3x)

domain

g (x) = x^{2} - 3 x

x \leq 0 or x \geq 3

Interval Notation

(- \infty, 0] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 3

The function domain

x \leq 0 or x \geq 3

f (x) = - 8 x + 3

f (x) = \frac{1}{2} x^{2} + x - 1

f (x) = \frac{x + 6}{x ^{2} + 2 x - 8}

f (x) = - x - 12

f (x) = \frac{5 x + 5}{9 + 2 x}

What is the domain of g(x)=sqrt(x^2-3x) ?
The domain of g(x)=sqrt(x^2-3x) is x<= 0\lor x>= 3