What is the domain of (sqrt(9-x^2))/x ?

The domain of (sqrt(9-x^2))/x is -3<= x<0\lor 0<x<= 3

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domain of (sqrt(9-x^2))/x

domain

\frac{9 - x ^{2}}{x}

- 3 \leq x < 0 or 0 < x \leq 3

Interval Notation

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq 3

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 3 \leq x < 0 or 0 < x \leq 3

y = arccos (\frac{- x + 2}{2}) + \frac{π}{2}

\frac{3 x ^{2} - 10 x - 8}{x - 4}

- 4 x + 1

- 4 x + 4

\frac{48000}{100 - x}

What is the domain of (sqrt(9-x^2))/x ?
The domain of (sqrt(9-x^2))/x is -3<= x<0\lor 0<x<= 3