What is the domain of f(x)= 1/((x^2-4)) ?

The domain of f(x)= 1/((x^2-4)) is x 2

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domain of f(x)= 1/((x^2-4))

domain

f (x) = \frac{1}{( x ^{2} - 4 )}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

f (x) = x^{3} - 12

f (x) = \frac{2 x - 1}{x ^{2} + 9 x}

y = 2^{- x} - 7

f (x) = 4^{x - 3}

x^{2} + \frac{16}{x}

What is the domain of f(x)= 1/((x^2-4)) ?
The domain of f(x)= 1/((x^2-4)) is x<-2\lor-2<x<2\lor x>2