What is the domain of 1/(sqrt(2x-1)) ?

The domain of 1/(sqrt(2x-1)) is x> 1/2

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domain of 1/(sqrt(2x-1))

domain

\frac{1}{2 x - 1}

x > \frac{1}{2}

Interval Notation

(\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

Find undefined (singularity) points:

x = \frac{1}{2}

Combine real regions and undefined points for final function domain

x > \frac{1}{2}

\frac{3 x - 5}{2}

\frac{2 x + 120}{ln ( 5 x - 20 )}

g (x) = 3 x - 2

f (x) = \frac{7 x + 2}{x ^{2} - 9}

\frac{4 - x ^{2}}{2 - x}