What is the domain of f(x)=sqrt(-5x^2+5) ?

The domain of f(x)=sqrt(-5x^2+5) is -1<= x<= 1

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domain of f(x)=sqrt(-5x^2+5)

domain

f (x) = - 5 x^{2} + 5

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

The function domain

- 1 \leq x \leq 1

f (x) = 1 - \frac{1}{x ^{2}}

y = 0.3 (x - 4)^{2} - 7.5

\frac{7}{7 x}

\frac{- x + 5}{- 4 x + 8}

y = \frac{x ^{2} - 4 x + 3}{x - 1}

What is the domain of f(x)=sqrt(-5x^2+5) ?
The domain of f(x)=sqrt(-5x^2+5) is -1<= x<= 1