What is the domain of f(x)=sqrt(175x^2-x) ?

The domain of f(x)=sqrt(175x^2-x) is x = 1/175

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(175x^2-x)

domain

f (x) = 175 x^{2} - x

x \leq 0 or x \geq \frac{1}{175}

Interval Notation

(- \infty, 0] \cup [\frac{1}{175}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq \frac{1}{175}

The function domain

x \leq 0 or x \geq \frac{1}{175}

\frac{2 x}{x ^{2} + 3 x}

y^{3} = x

f (x) = \frac{x + 1}{x ^{2} + x - 2}

f (x) = 4 x^{2} + 4 x - 2

f (x) = 3 x^{4} - 4 x^{3} - 12 x^{2}

What is the domain of f(x)=sqrt(175x^2-x) ?
The domain of f(x)=sqrt(175x^2-x) is x<= 0\lor x>= 1/175