What is the domain of f(x)=ln(sqrt(2x+1)) ?

The domain of f(x)=ln(sqrt(2x+1)) is x>-1/2

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domain of f(x)=ln(sqrt(2x+1))

domain

f (x) = ln (2 x + 1)

x > - \frac{1}{2}

Interval Notation

(- \frac{1}{2}, \infty)

Solution steps

Find positive values for logs:

x > - \frac{1}{2}

The function domain

x > - \frac{1}{2}

\frac{x + 9}{( x - 1 ) ( x - 7 )}

8 x

f (x) = 2 (x + 6)^{2} + 5

f (x) = - \frac{x}{x - 1}

8 x - 5

What is the domain of f(x)=ln(sqrt(2x+1)) ?
The domain of f(x)=ln(sqrt(2x+1)) is x>-1/2