What is the domain of (x+1)/(x^2-9x) ?

The domain of (x+1)/(x^2-9x) is x 9

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domain of (x+1)/(x^2-9x)

domain

\frac{x + 1}{x ^{2} - 9 x}

x < 0 or 0 < x < 9 or x > 9

Interval Notation

(- \infty, 0) \cup (0, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = 0

The function domain

x < 0 or 0 < x < 9 or x > 9

5 x

\frac{1}{4 x ^{2} + 5} \cdot \frac{1}{5 x - 2}

y = 5 - x

f (z) = \frac{1}{z}

f (x) = \frac{x + 6}{x ^{3} - x}

What is the domain of (x+1)/(x^2-9x) ?
The domain of (x+1)/(x^2-9x) is x<0\lor 0<x<9\lor x>9