What is the domain of (x^2-4x+3)/(x+1) ?

The domain of (x^2-4x+3)/(x+1) is x -1

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domain of (x^2-4x+3)/(x+1)

domain

\frac{x ^{2} - 4 x + 3}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = x + 3 + 1

f (x) = - 6 x 5 2 x + 6

\frac{1}{7 - 3 x}

f (x) = \frac{x ^{2} + 4}{x ^{2} - 2 x + 8}

f (x) = \frac{( x - 2 )}{( x - 3 ) ^{2}}

What is the domain of (x^2-4x+3)/(x+1) ?
The domain of (x^2-4x+3)/(x+1) is x<-1\lor x>-1