What is the domain of 1/(log_{10)(x+1)} ?

The domain of 1/(log_{10)(x+1)} is -1 0

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domain of 1/(log_{10)(x+1)}

domain

\frac{1}{lo g _{10} ( x + 1 )}

- 1 < x < 0 or x > 0

Interval Notation

(- 1, 0) \cup (0, \infty)

Solution steps

Find positive values for logs:

x > - 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 < x < 0 or x > 0

f (x) = \frac{4}{x - 1} + 1

\frac{x ^{2} + 5}{x + 2}

f (x) = \frac{4}{3 x - 2}

\frac{1}{x - 3} + 7

f (x) = 2 - x + \cdot (- 3)

What is the domain of 1/(log_{10)(x+1)} ?
The domain of 1/(log_{10)(x+1)} is -1<x<0\lor x>0