What is the domain of f(x)= 1/((x-2)(3x-1)) ?

The domain of f(x)= 1/((x-2)(3x-1)) is x 2

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domain of f(x)= 1/((x-2)(3x-1))

domain

f (x) = \frac{1}{( x - 2 ) ( 3 x - 1 )}

x < \frac{1}{3} or \frac{1}{3} < x < 2 or x > 2

Interval Notation

(- \infty, \frac{1}{3}) \cup (\frac{1}{3}, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = \frac{1}{3}

The function domain

x < \frac{1}{3} or \frac{1}{3} < x < 2 or x > 2

f (x) = \frac{3 x + 7}{2} g (x) = x

f (x) = \frac{x - 3}{x + 3} - 1

f (x) = 5 x^{2} - 25

y = 6 sin (x) + 8 cos (x)

f (x) = \frac{8 x}{1 - x - 3}

What is the domain of f(x)= 1/((x-2)(3x-1)) ?
The domain of f(x)= 1/((x-2)(3x-1)) is x< 1/3 \lor 1/3 <x<2\lor x>2