What is the domain of (ln(x^2))/(e^{2x)-e} ?

The domain of (ln(x^2))/(e^{2x)-e} is x 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of (ln(x^2))/(e^{2x)-e}

domain

\frac{ln ( x ^{2} )}{e ^{2 x} - e}

x < 0 or 0 < x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, 0) \cup (0, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find positive values for logs:

x < 0 or x > 0

Find undefined (singularity) points:

x = \frac{1}{2}

Combine real regions and undefined points for final function domain

x < 0 or 0 < x < \frac{1}{2} or x > \frac{1}{2}

f (x) = \frac{3 x}{x - 6}

3 - 2 x + 1

f (x) = 4 - 24 - 2 x - x^{2}

2 - 4 x

f (x) = \frac{x + 2}{x ^{2} + 4}

What is the domain of (ln(x^2))/(e^{2x)-e} ?
The domain of (ln(x^2))/(e^{2x)-e} is x<0\lor 0<x< 1/2 \lor x> 1/2