What is the domain of f(x)=x^2+(16)/x ?

The domain of f(x)=x^2+(16)/x is x 0

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domain of f(x)=x^2+(16)/x

domain

f (x) = x^{2} + \frac{16}{x}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

\frac{5 x + 25}{9}

f (r) = 3.14 r^{2}

\frac{8}{3 - x}

f (x) = 16 - (x - 1)^{2}

f (x) = \frac{3 x + 6}{x - 2}

What is the domain of f(x)=x^2+(16)/x ?
The domain of f(x)=x^2+(16)/x is x<0\lor x>0