What is the domain of (sqrt(x^2-16))/(2x-3) ?

The domain of (sqrt(x^2-16))/(2x-3) is x = 4

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domain of (sqrt(x^2-16))/(2x-3)

domain

\frac{x ^{2} - 16}{2 x - 3}

x \leq - 4 or x \geq 4

Interval Notation

(- \infty, - 4] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

Find undefined (singularity) points:

x = \frac{3}{2}

Combine real regions and undefined points for final function domain

x \leq - 4 or x \geq 4

- lo g_{10} (3 x - 5) + 5

0.36 x^{2} + 40

f (x) = \frac{\frac{3 x}{2} + 4}{\frac{x}{4}}

f (x) = \frac{t + 2}{15 - t}

\frac{12}{x ^{2} - 25} - 3

What is the domain of (sqrt(x^2-16))/(2x-3) ?
The domain of (sqrt(x^2-16))/(2x-3) is x<=-4\lor x>= 4