What is the domain of (-8x+9)/(1+x) ?

The domain of (-8x+9)/(1+x) is x -1

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domain of (-8x+9)/(1+x)

domain

\frac{- 8 x + 9}{1 + x}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = arcsin (\frac{x - 3}{2})

y = 21 x + 9 x^{2} - x^{3}

f (x) = lo g_{10} (- (x - 5)) + 4

f (x) = - 1 + lo g_{2} (x - 5)

f (x) = 2 x^{2} - x, x > 1

What is the domain of (-8x+9)/(1+x) ?
The domain of (-8x+9)/(1+x) is x<-1\lor x>-1