What is the domain of g(x)= 1/(x-2) ?

The domain of g(x)= 1/(x-2) is x 2

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domain of g(x)= 1/(x-2)

domain

g (x) = \frac{1}{x - 2}

x < 2 or x > 2

Interval Notation

(- \infty, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2

The function domain

x < 2 or x > 2

\frac{sin ( x )}{cos ( x ) + 1}

f (x) = 4 t^{2} - 6

f (x) = \frac{1}{s - 3}

f (x) = \frac{( 1 - e ^{x} )}{ln ( x )}

f (x) = \frac{x + 9}{x ^{2} - 1}

What is the domain of g(x)= 1/(x-2) ?
The domain of g(x)= 1/(x-2) is x<2\lor x>2