What is the domain of f(x)=sqrt((2x-3)/(x-2)) ?

The domain of f(x)=sqrt((2x-3)/(x-2)) is x 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((2x-3)/(x-2))

domain

f (x) = \frac{2 x - 3}{x - 2}

x \leq \frac{3}{2} or x > 2

Interval Notation

(- \infty, \frac{3}{2}] \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq \frac{3}{2} or x > 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x \leq \frac{3}{2} or x > 2

\frac{( 2 x )}{x ^{2} - 1}

f (x) = \frac{3 x + 1}{5}

f (x) = 2 x^{2} + 8 x - 1

f (x) = lo g_{2} (2 - 3 x)

f (x) = \frac{x + 1}{x ^{2} + 4}

What is the domain of f(x)=sqrt((2x-3)/(x-2)) ?
The domain of f(x)=sqrt((2x-3)/(x-2)) is x<= 3/2 \lor x>2