What is the domain of f(x)=(4z)/(z^2-1) ?

The domain of f(x)=(4z)/(z^2-1) is z 1

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domain of f(x)=(4z)/(z^2-1)

domain

f (x) = \frac{4 z}{z ^{2} - 1}

z < - 1 or - 1 < z < 1 or z > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

z = 1, z = - 1

The function domain

z < - 1 or - 1 < z < 1 or z > 1

\frac{5 x ^{3} - 9}{x ^{3} + 13 x ^{2} + 42 x}

f (x) = \frac{4 x}{5 ( x - 1 ) ( x - 8 )}

5 x + 25

f (x) = \frac{( 2 x - 7 )}{( x - 3 )}

y = \frac{x + 7}{x ^{2} + 1}

What is the domain of f(x)=(4z)/(z^2-1) ?
The domain of f(x)=(4z)/(z^2-1) is z<-1\lor-1<z<1\lor z>1