What is the domain of y=tan(2x) ?

The domain of y=tan(2x) is pi/2 n<= x< pi/4+pi/2 n\lor pi/4+pi/2 n<x< pi/2+pi/2 n

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domain of y=tan(2x)

domain

y = tan (2 x)

\frac{π}{2} n \leq x < \frac{π}{4} + \frac{π}{2} n or \frac{π}{4} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

Interval Notation

[\frac{π}{2} n, \frac{π}{4} + \frac{π}{2} n) \cup (\frac{π}{4} + \frac{π}{2} n, \frac{π}{2} + \frac{π}{2} n)

Solution steps

Take the denominator(s) of

tan (2 x)

and compare to zero:

x = \frac{π}{4} + \frac{π}{2} n

Periodicity of

tan (2 x) : \frac{π}{2}

Combine period:

\frac{π}{2} n \leq x < \frac{π}{2} + \frac{π}{2} n

and undefined points.

The domain is

\frac{π}{2} n \leq x < \frac{π}{4} + \frac{π}{2} n or \frac{π}{4} + \frac{π}{2} n < x < \frac{π}{2} + \frac{π}{2} n

f (x) = \frac{x - 5}{5 - x}

y = \frac{2 x ^{2} - 3}{x ^{2} + 2 x + 1}

y = - 2 x + 125 {3, 9 \leq y \leq 50}

y = x^{2} - x - ln (x)

f (x) = \frac{( x + 1 ) ^{3}}{( x - 1 ) ^{2}}

What is the domain of y=tan(2x) ?
The domain of y=tan(2x) is pi/2 n<= x< pi/4+pi/2 n\lor pi/4+pi/2 n<x< pi/2+pi/2 n