What is the domain of f(x)=sqrt(y+6) ?

The domain of f(x)=sqrt(y+6) is y>=-6

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domain of f(x)=sqrt(y+6)

domain

f (x) = y + 6

y \geq - 6

Interval Notation

[- 6, \infty)

Solution steps

Find non-negative values for radicals:

y \geq - 6

The function domain

y \geq - 6

f (x) = 3 x^{2} + 7 x + 2

f (x) = x^{\frac{1}{3}} (x^{2} - 63)

(\frac{2}{3})^{x - 3} - 2

f (x) = 1 - \frac{2 x + 3}{x - 1}

f (x) = \frac{3}{x + 3}