What is the domain of arccos(sqrt(3x^2-2)) ?

The domain of arccos(sqrt(3x^2-2)) is -1<= x<=-sqrt(2/3)\lor sqrt(2/3)<= x<= 1

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domain of arccos(sqrt(3x^2-2))

domain

arccos (3 x^{2} - 2)

- 1 \leq x \leq - \frac{2}{3} or \frac{2}{3} \leq x \leq 1

Interval Notation

[- 1, - \frac{2}{3}] \cup [\frac{2}{3}, 1]

Solution steps

Find known functions domain restrictions:

- 1 \leq x \leq - \frac{2}{3} or \frac{2}{3} \leq x \leq 1

The function domain

- 1 \leq x \leq - \frac{2}{3} or \frac{2}{3} \leq x \leq 1

f (x) = e^{0.5 x} + 4 e^{- 0.5 x}

\frac{x ^{2} - 8 x + 15}{x ^{2} - 7 x + 12}

f (x) = - 4 - x

f (x) = \frac{x ^{2} - 6 x + 8}{x - 4}

- lo g_{2} (x - 1)

What is the domain of arccos(sqrt(3x^2-2)) ?
The domain of arccos(sqrt(3x^2-2)) is -1<= x<=-sqrt(2/3)\lor sqrt(2/3)<= x<= 1