What is the domain of f(x)=(sin(x))/(cos(x)+1) ?

The domain of f(x)=(sin(x))/(cos(x)+1) is 2pin<= x<pi+2pin\lor pi+2pin<x<2pi+2pin

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domain of f(x)=(sin(x))/(cos(x)+1)

domain

f (x) = \frac{sin ( x )}{cos ( x ) + 1}

2 πn \leq x < π + 2 πn or π + 2 πn < x < 2 π + 2 πn

Interval Notation

[2 πn, π + 2 πn) \cup (π + 2 πn, 2 π + 2 πn)

Solution steps

Take the denominator(s) of

\frac{sin ( x )}{cos ( x ) + 1}

and compare to zero:

x = π + 2 πn

Periodicity of

\frac{sin ( x )}{cos ( x ) + 1} : 2 π

Combine period:

2 πn \leq x < 2 π + 2 πn

and undefined points.

The domain is

2 πn \leq x < π + 2 πn or π + 2 πn < x < 2 π + 2 πn

f (x) = x + 2, x \geq 0

\frac{4 x}{5 x - 8}

- x^{2} + 2 x + 3

f (x) = lo g_{5} (x^{2} + 1)

g (x) = \frac{x - 2}{x ^{2} + 4 x + 4}

What is the domain of f(x)=(sin(x))/(cos(x)+1) ?
The domain of f(x)=(sin(x))/(cos(x)+1) is 2pin<= x<pi+2pin\lor pi+2pin<x<2pi+2pin