What is the domain of 1/(2xsqrt(9+ln(x))) ?

The domain of 1/(2xsqrt(9+ln(x))) is x> 1/(e^9)

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domain of 1/(2xsqrt(9+ln(x)))

domain

\frac{1}{2 x 9 + ln ( x )}

x > \frac{1}{e ^{9}}

Interval Notation

(\frac{1}{e ^{9}}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{e ^{9}}

Find undefined (singularity) points:

x = \frac{1}{e ^{9}}

Combine real regions and undefined points for final function domain

x > \frac{1}{e ^{9}}

y = 2 csc (3 x - π) + 1

2 (x - 3)^{2} + 4

ln (16 - x^{2})

2 arctan (x)

\frac{x ^{2} - 9}{3}

What is the domain of 1/(2xsqrt(9+ln(x))) ?
The domain of 1/(2xsqrt(9+ln(x))) is x> 1/(e^9)