What is the domain of f(x)=sqrt(6/(x-1)-5/(x-2)+2) ?

The domain of f(x)=sqrt(6/(x-1)-5/(x-2)+2) is x = 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(6/(x-1)-5/(x-2)+2)

domain

f (x) = \frac{6}{x - 1} - \frac{5}{x - 2} + 2

x \leq - \frac{1}{2} or 1 < x < 2 or x \geq 3

Interval Notation

(- \infty, - \frac{1}{2}] \cup (1, 2) \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{1}{2} or 1 < x < 2 or x \geq 3

Find undefined (singularity) points:

x = 1, x = 2

Combine real regions and undefined points for final function domain

x \leq - \frac{1}{2} or 1 < x < 2 or x \geq 3

y = - x^{3}

f (x) = 1 1^{x} + 2

f (x) = 6 x^{4} + 7 x^{2} - 8 x + 9

f (x) = lo g_{2} (\frac{3 x - 1}{x - 1} + 1)

f (x) = - x^{2} + 20 x - 95

What is the domain of f(x)=sqrt(6/(x-1)-5/(x-2)+2) ?
The domain of f(x)=sqrt(6/(x-1)-5/(x-2)+2) is x<=-1/2 \lor 1<x<2\lor x>= 3