What is the domain of f(x)=sqrt(t+9) ?

The domain of f(x)=sqrt(t+9) is t>=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(t+9)

domain

f (x) = t + 9

t \geq - 9

Interval Notation

Solution steps

Find non-negative values for radicals:

t \geq - 9

The function domain

t \geq - 9

f (x) = ∣ 2 - x ∣

f (x) = \frac{( x ^{2} - 1 )}{x ^{2} + 4}

f (x) = 3 + x + 4

f (x) = 5 x^{2} - 40 x + 61

f (x) = \frac{1}{- 3 x + 1}