What is the domain of f(x)=sqrt(x^2-3x-18) ?

The domain of f(x)=sqrt(x^2-3x-18) is x = 6

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domain of f(x)=sqrt(x^2-3x-18)

domain

f (x) = x^{2} - 3 x - 18

x \leq - 3 or x \geq 6

Interval Notation

(- \infty, - 3] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 6

The function domain

x \leq - 3 or x \geq 6

f (x) = \frac{x - 4}{1 - x}

y = x^{2} - 3 x

f (x) = \frac{2 x - 4}{x ^{2} - 4}

3 5 - 3 5 - x

y = \frac{6 x + 5}{4 x - 3}

What is the domain of f(x)=sqrt(x^2-3x-18) ?
The domain of f(x)=sqrt(x^2-3x-18) is x<=-3\lor x>= 6