What is the domain of f(x)=sqrt((x+1)(x+4)) ?

The domain of f(x)=sqrt((x+1)(x+4)) is x =-1

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domain of f(x)=sqrt((x+1)(x+4))

domain

f (x) = (x + 1) (x + 4)

x \leq - 4 or x \geq - 1

Interval Notation

(- \infty, - 4] \cup [- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq - 1

The function domain

x \leq - 4 or x \geq - 1

- 27 - 27 x - 9 x^{2} - x^{3}

\frac{2}{3 x - 5}

g (x) = x - 10

x^{2} - x - 12

\frac{1}{1 - 3 x}

What is the domain of f(x)=sqrt((x+1)(x+4)) ?
The domain of f(x)=sqrt((x+1)(x+4)) is x<=-4\lor x>=-1