What is the domain of y=arccos((x+1)/2)-pi/2 ?

The domain of y=arccos((x+1)/2)-pi/2 is -3<= x<= 1

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domain of y=arccos((x+1)/2)-pi/2

domain

y = arccos (\frac{x + 1}{2}) - \frac{π}{2}

- 3 \leq x \leq 1

Interval Notation

[- 3, 1]

Solution steps

Find known functions domain restrictions:

- 3 \leq x \leq 1

The function domain

- 3 \leq x \leq 1

- π

(x^{2} - 4)^{\frac{3}{4}}

- 2 (1 + 10 x)

y = 2 x + 6 - 4

f (x, y) = x^{2} y^{2} - 2 x^{2} - 2 y^{2} = 0

What is the domain of y=arccos((x+1)/2)-pi/2 ?
The domain of y=arccos((x+1)/2)-pi/2 is -3<= x<= 1