What is the domain of f(x)=arctan((x+1)/(x-1)) ?

The domain of f(x)=arctan((x+1)/(x-1)) is x 1

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domain of f(x)=arctan((x+1)/(x-1))

domain

f (x) = arctan (\frac{x + 1}{x - 1})

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = \frac{8 x + 9}{7 x - 8}

\frac{4 + x}{1 - x}

x^{2} + 2 x - 1 - (2 x^{2} - 3 x + 6)

\frac{2 - x}{( x + 1 ) ^{5}}

(x + 3)^{2}

What is the domain of f(x)=arctan((x+1)/(x-1)) ?
The domain of f(x)=arctan((x+1)/(x-1)) is x<1\lor x>1