What is the critical f(x)=3.1+6.6x-2.3x^2 ?

The critical f(x)=3.1+6.6x-2.3x^2 is x= 33/23

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critical f(x)=3.1+6.6x-2.3x^2

critical points

f (x) = 3.1 + 6.6 x - 2.3 x^{2}

x = \frac{33}{23}

Solution steps

3.1 + 6.6 x - 2.3 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{33}{23}

Identify critical points not in

f (x)

domain

Domain of

3.1 + 6.6 x - 2.3 x^{2} : - \infty < x < \infty

All critical points are in domain

x = \frac{33}{23}

\frac{4 x + 7}{3 x - 4}

f (x) = 3 x^{2} + 2 x - 6

y = - 2 sin (4 x + \frac{π}{2})

ln (x - 5)

f (x) = \frac{1}{2} x^{2} + 4 x + 5

What is the critical f(x)=3.1+6.6x-2.3x^2 ?
The critical f(x)=3.1+6.6x-2.3x^2 is x= 33/23