What is the domain of sqrt(x^2+x)-x ?

The domain of sqrt(x^2+x)-x is x = 0

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domain of sqrt(x^2+x)-x

domain

x^{2} + x - x

x \leq - 1 or x \geq 0

Interval Notation

(- \infty, - 1] \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 0

The function domain

x \leq - 1 or x \geq 0

f (x) = \frac{1}{2 x ^{2}}

f (x) = \frac{1}{x - 2} + 3

f (x) = \frac{1}{x - 2} + 1

f (x) = - x^{2} + 8 x - 12

f (x) = ∣ x - 7 ∣

What is the domain of sqrt(x^2+x)-x ?
The domain of sqrt(x^2+x)-x is x<=-1\lor x>= 0