What is the domain of sqrt(9-5x^2) ?

The domain of sqrt(9-5x^2) is -3/(sqrt(5))<= x<= 3/(sqrt(5))

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domain of sqrt(9-5x^2)

domain

9 - 5 x^{2}

- \frac{3}{5} \leq x \leq \frac{3}{5}

Interval Notation

[- \frac{3}{5}, \frac{3}{5}]

Solution steps

Find non-negative values for radicals:

- \frac{3}{5} \leq x \leq \frac{3}{5}

The function domain

- \frac{3}{5} \leq x \leq \frac{3}{5}

y = lo g_{10} (x^{2} + 2 x - 3)

f (x) = \frac{1 - 3 a}{7}

f (x) = \frac{( 1 - x )}{1 + x}

y = 2^{x + 4}

\frac{( x + 5 )}{x ^{2} - 3 x}

What is the domain of sqrt(9-5x^2) ?
The domain of sqrt(9-5x^2) is -3/(sqrt(5))<= x<= 3/(sqrt(5))