What is the domain of f(x)= 1/((x^2-x)) ?

The domain of f(x)= 1/((x^2-x)) is x 1

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domain of f(x)= 1/((x^2-x))

domain

f (x) = \frac{1}{( x ^{2} - x )}

x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = 0

The function domain

x < 0 or 0 < x < 1 or x > 1

f (x) = \frac{x - 1}{x + 1}

f (x) = \frac{4 x ^{2} + 6 x - 2}{4 x - 6}

\frac{x ( x - 5 ) ^{2}}{4}

\frac{2 x}{x ^{2} - 25}

f (x) = lo g_{2} (- x)

What is the domain of f(x)= 1/((x^2-x)) ?
The domain of f(x)= 1/((x^2-x)) is x<0\lor 0<x<1\lor x>1