What is the domain of f(x)= 1/(x^2+2x) ?

The domain of f(x)= 1/(x^2+2x) is x 0

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domain of f(x)= 1/(x^2+2x)

domain

f (x) = \frac{1}{x ^{2} + 2 x}

x < - 2 or - 2 < x < 0 or x > 0

Interval Notation

(- \infty, - 2) \cup (- 2, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 2

The function domain

x < - 2 or - 2 < x < 0 or x > 0

f (x) = x^{2} - 2 x - ln (x + 1)

f (x) = \frac{1}{x ^{2}} + \frac{1}{x ^{3}}

f (x) = 15 x^{2} + 5 x - 1

f (x) = 2 x^{3} - 9 x^{2} + 12 x + 5

y = \frac{x ^{2}}{x ^{2} - 9}

What is the domain of f(x)= 1/(x^2+2x) ?
The domain of f(x)= 1/(x^2+2x) is x<-2\lor-2<x<0\lor x>0