What is the domain of f(x)= 1/(\sqrt[4]{x^2)-5x} ?

The domain of f(x)= 1/(\sqrt[4]{x^2)-5x} is x 1/25

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domain of f(x)= 1/(\sqrt[4]{x^2)-5x}

domain

f (x) = \frac{1}{4 x ^{2} - 5 x}

x < 0 or 0 < x < \frac{1}{25} or x > \frac{1}{25}

Interval Notation

(- \infty, 0) \cup (0, \frac{1}{25}) \cup (\frac{1}{25}, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

Find undefined (singularity) points:

x = \frac{1}{25}, x = 0

Combine real regions and undefined points for final function domain

x < 0 or 0 < x < \frac{1}{25} or x > \frac{1}{25}

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x^{4} - x^{3} - 6 x^{2}

f (x) = \frac{x + 3}{x + 5}

What is the domain of f(x)= 1/(\sqrt[4]{x^2)-5x} ?
The domain of f(x)= 1/(\sqrt[4]{x^2)-5x} is x<0\lor 0<x< 1/25 \lor x> 1/25