What is the domain of f(x)= 1/((x+5)^2) ?

The domain of f(x)= 1/((x+5)^2) is x -5

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domain of f(x)= 1/((x+5)^2)

domain

f (x) = \frac{1}{( x + 5 ) ^{2}}

x < - 5 or x > - 5

Interval Notation

(- \infty, - 5) \cup (- 5, \infty)

Solution steps

Find undefined (singularity) points:

x = - 5

The function domain

x < - 5 or x > - 5

f (x) = lo g_{10} (80 - 0.5 x)

f (x) = lo g_{5} (x^{2} + 16)

f (x) = \frac{1}{lo g _{10} ( x + 2 )}

f (x) = lo g_{2} (\frac{- x - 1}{x - 1})

f (x) = 3 \cdot (- 7)

What is the domain of f(x)= 1/((x+5)^2) ?
The domain of f(x)= 1/((x+5)^2) is x<-5\lor x>-5