What is the domain of f(x)= 5/(x^2+x-12) ?

The domain of f(x)= 5/(x^2+x-12) is x 3

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domain of f(x)= 5/(x^2+x-12)

domain

f (x) = \frac{5}{x ^{2} + x - 12}

x < - 4 or - 4 < x < 3 or x > 3

Interval Notation

(- \infty, - 4) \cup (- 4, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 4

The function domain

x < - 4 or - 4 < x < 3 or x > 3

\frac{x - 1}{x + 5}

f (x) = x^{3} + x^{2} - 2 x + 3

f (x) = \frac{4 x + 8}{( x - 2 ) ( x + 6 )}

3 x + \frac{6}{x} - \frac{1}{x ^{3}}

ln ((x - 12)^{2})

What is the domain of f(x)= 5/(x^2+x-12) ?
The domain of f(x)= 5/(x^2+x-12) is x<-4\lor-4<x<3\lor x>3