What is the domain of f(x)=sqrt(x-9/x) ?

The domain of f(x)=sqrt(x-9/x) is -3 = 3

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domain of f(x)=sqrt(x-9/x)

domain

f (x) = x - \frac{9}{x}

- 3 \leq x < 0 or x \geq 3

Interval Notation

[- 3, 0) \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

- 3 \leq x < 0 or x \geq 3

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 3 \leq x < 0 or x \geq 3

f (x) = \frac{20 - 4 x}{2}

\frac{( 2 x ^{2} + 2 x - 12 )}{( x ^{2} + 4 x - 5 )}

f (x) = lo g_{3} ((x + 2)^{2})

f (x) = \frac{1}{x - 3}

\frac{7 x}{8 x - 9}

What is the domain of f(x)=sqrt(x-9/x) ?
The domain of f(x)=sqrt(x-9/x) is -3<= x<0\lor x>= 3